If s(x) = x – 7 and t(x) = 4x2 – x + 3, 4(x – 7)2 – x – 7 + 3 4(x – 7)2 – (x – 7) + 3 (4x2 – x + 3) – 7 (4x2 – x + 3)(x – 7)

Answers:

1) (s o t)(x)=4x^2-x-4

2) (t o s)(x)=4(x-7)^2-(x-7)+3

Solution:

1) (s o t)(x)=s(t(x))=s(4x^2-x+3)=(4x^2-x+3)-7=4x^2-x+3-7

(s o t)(x)=4x^2-x-4

2) (t o s)(x)=t(s(x))=t(x-7)=4(x-7)^2-(x-7)+3

(t o s)(x)=4(x-7)^2-(x-7)+3

c-   36

taxicab circle radius 9 has 4(9) = 36 points

yx = 36

step-by-step explanation:

cos f = opposite side/ hypotenuse

cos f = yw / yx

we know cos f = 4/9 and yw =16

4/9 = 16/yx

multiply each side by yx

4/9 yx = 16/ yx * yx

4/9 yx = 16

multiply each side by 9/4

9/4 * 4/9 yx = 16 *9/4

yx = 36