What is the value of f(−1) when f(x)=2x+2 ? f(−1)= what is the value of the function at x=−2? the graph goes with this question. y=−2 y = 0 y = 2 y = 3

0; 2

Step-by-step explanation:

Function:

f(x)=2x+2

f(-1) = 2(-1) + 2 = -2 + 2 = 0

f(-1) = 0

Graph:

Look at the point on the graph that has x = -2. The point is (-2, 2), so y = 2.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)