How do i graph q is greater than -1.3 on a number line

an open circle on -1.3 on the line and draw a line to the right with an arrow.

Step-by-step explanation:

On your number line, draw an open circle on -1.3 and then draw a line on the number line going to the right and ending with an arrow at the end.  The open circle means that it is that starting point, but is not equal to it.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option