Determine the standard form of the equation of the line that passes through ( -5,0 ) ( 0 ,-9)

The general form for a line through two points (a,b) and (c,d) is

(c-a)(y-b)=(d-b)(x-a)

This is better than the slope forms because it works in the no slope case, as does the standard form.

If you haven't seen it before, it works because when (x,y)=(a,b) we get (c-a)(b-b)=(d-b)(a-a), both sides zero, and when (x,y)=(c,d) we get (c-a)(d-b)=(d-b)(c-a), clearly equal sides.

Here we have

(0 - -5)(y - 0) = (-9 - 0)(x - - 5)

5y = -9(x+5)

5y = -9x - 45

9x + 5y = -45

Ironically there are two standards for standard form; one with the constant alone on the right and one with the whole thing equal to zero.  I like the constant alone.

9x + 5y = -45

Check:

We check each point is on the line

(-5,0)

9(-5) + 5(0) = -45, good

(0, -9)

9(0) + 5(-9) = -45, good again

it is a reproduction.

step-by-step explanation:

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse