Jasper is giving four non-collinear points. how many different triangles can he draw using these points?

4

Step-by-step explanation:

There are 4 ways to ignore one of the points. The other 3 can be connected to form a triangle.

More formally, the number of ways that 4 items can be chosen 3 at a time is given by ...

... C(4, 3) = 4!/(3!(4-3)!) = 4/1 = 4

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.