An airplane is flying 38,900 ft above the ground. angle of depression from the plane to the base of the building is 4.3°. how far must a plane fly horizontally to be directly over the building?

Height of the airplane above the ground = 38,900 ft.

Angle of depression from the plane to the base of the building = 4.3°.

So, we could apply tangent trigonometric ratio:

tan 4.3° =

0.07519 =

On cross multiply, we get

0.07519 x= 38,900.

Dividing both sides by 0.07519, we get

x= 517356.03 ft.

answer is because 4×10=40

and 98×4= is 392

40,392

where is the gragh

step-by-step explanation: