Find the 66th term of the arithmetic sequence 3, 13, 23, ,13,

66th term of given arithmetic sequence is 653

Given that;

Arithmetic sequence = 3, 13, 23, ...

Find:

66th term of given arithmetic sequence

Computation:

d = a2 - a1

d = 13 - 3

d = 10

So,

a66 = a + 65d

a66 = 3 + 65(10)

a66 = 3 + 650

a66 = 653

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653

Step-by-step explanation:

I will need to assume that you meant 3, 13, 23, 33, 43, ...

Here the first term is 3 and the common difference is 10.  The formula is a(n) = 3 + 10(n-1)

Thus, the 66th term is 3 + 10(66-1), or 3 + 10(65), or 653.

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