The sum of three numbers is 18. the sum of the first and second numbers is 15, and the first number is 3 times the third number. find the numbers.

9, 6, and 3 are the numbers.

-TTL

3 , 6 , 9

Step-by-step explanation:

suppose these three numbers are a, b, and c. we can write the following equations:  

#1 a+b+c = 18

#2 a+b = 15

#3 a = 3c  

if we subtract #2 from #1 we have c = 3. From #3 we have a = 3(3) = 9. Finally, since a+b+c = 18 we plug in our known values for a and c to obtain b = 6. therefore our three numbers are a = 9, b = 6, c = 3.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2