Is it possible that a parallelogram with length of the sides equal to 4 cm and 7 cm has the length of one of the diagonals 2 cm?

No, it's not possible for one of the diagonals to be 2 cm.

This means that 2 adjacent sides of the parallelogram will be 2 sides of each the triangles.

Since the third side of the triangle which is the diagonal of the parallelogram is unknown, we can have an idea of the range of the diagonal by using a theorem known as the Triangle inequality theorem. This theorem states that the sum of any two sides of any triangle is greater than or equal to the third side.

Thus; 11 ≥ x

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No.

Step-by-step explanation:

Two adjacent sides and a diagonal form a triangle. When the sides are 4 and 7, the triangle inequality tells you the remaining side (of the triangle) must be between 7-4 = 3 and 7+4 = 11. A diagonal length of 2 is not possible.

Another way to put this is that the sum of the two shortest sides (4 and 2, in this case) must exceed the longest side (7 in this case). That sum does not.

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}