Ajar contains nickels and dimes. there are 20 coins in the jar, and the total value of the coins is $1.40. write and solve a system of equations to determine the number of nickels and dimes in the jar.

.5x+.10y=$1.40
Where x equals the number of nickels and u equals the number of dimes

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)