In january, bangkok is hotter than cape town while cape town is hotter than moscow. which inequality correctly compares the temperatures of the three cities?

Answer-

Solution-

From general laws of physics, we know that, the more the heat content in a body, the more is the temperature. i.e as the temperature increases the body or system gets headed, vice-versa.

Let's assume,

Temperature of Bangkok = T₁

Temperature of Cape Town = T₂

Temperature of Moscow = T₃

As, Bangkok is hotter than Cape Town,

 ------------------------1

Then, Cape Town is hotter than Moscow,

 -----------------------2

Combing these two equations,

Therefore, this is the inequality that correctly compares the temperatures of the three cities.

the solution is h=10 because you add 9 to each side of the equation.

25.2

step-by-step explanation:

2+4x6-8/10= 25.2