The inside ring of packing tape has a diameter of 80 mm. the tape surrounding the ring is 8 mm beyond the ring. what is the distance around the outer edge of the tape? use 3.14 for π π . 301.44 mm 150.72 mm 48.28 mm 276.32 mm

301.44 mm

Step-by-step explanation:

Diameter of the inside ring of a packing tape = 80 mm

The tape surrounding the ring is 8 mm beyond the ring which means the diameter of the ring including the surrounding will be:

80 + 8 + 8 = 96 mm

and its radius will be = 96/2 = 48.

To find the distance around the outer edge of the tape, we need to calculate the circumference for the ring with the tape on it.

Circumference =

Circumference = 2 x 3.14 x 48 = 301.44 mm

Therefore,  the distance around the outer edge of the tape is 301.44 mm.

i'm sure goog can you get that answer

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west