Melinda and paul shovel driveways and sidewalks in the winter as a way to earn extra money. together they shoveled 450 square feet of sidewalk in 30 minutes. then melinda shoveled for 20 minutes while paul shoveled for 25 minutes to complete 345 square feet of driveway. how much more can paul shovel in 1 minute than melinda?

Paul can shovel 3 sq feet per minute more than Melinda.

Step-by-step explanation:

Let Melinda shovels per minute, 'x' sq feet area.

Let Paul shovels per minute, 'y' sq feet area.

Given - Melinda and Paul together shoveled 450 square feet of sidewalk in 30 minutes. Equation forms:

Factoring out 30 common, we get;

        .......(1)

Also given- Melinda shoveled for 20 minutes while Paul shoveled for 25 minutes to complete 345 square feet of driveway.

Factoring out 5 common, we get;

   ......(2)

Now, multiplying (1) by 4 and subtracting from (2) we get

y = 9

And

x = 6

So, we get that Melinda shovels 6 sq feet per minute and Paul shovels 9 square feet per minute.

This gives that, Paul can shovel sq feet per minute more than Melinda.

f

step-by-step explanation:

f

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0