Arectangle's length is 4 feet more than it's width. if the area of the rectangle is 396 square feet, what is its width, in feet?

18 feet

Step-by-step explanation:

Let the width of the rectangle to be x.

Therefore, the length which is 4 feet more than the width will be = x + 4

We know that the Area of a rectangle = L x W, so we will substitute the values of area, length and width in it to get:

Area = L x W

396 = (x + 4) (x)

396 = x^2 + 4x

x^2 + 4x - 396 = 0

Now we will factorize this quadratic equation:

x^2 + 4x - 396 = 0

x^2 + 22x - 18x -396 = 0

x (x + 22) - 18 (x + 22) = 0

x = -22 (ignore) and x = 18

So width is 18 feet and by adding 4 to it we can know the length which is 18 + 4 = 22 feet.

a) 7x=7

step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!