Solve the following addition problems. remember to carry as necessary. a. 995 lb. 6 oz. + 1,004 lb. 11 oz. b. 24 t. 1,507 lb. 12 oz. + 7 t. 938 lb. 6 oz. c. 6 t. 14 oz. + 11 t. 1,949 lb. + 8 oz. + 5 t. 49 lb. 15 oz.

a.   995 lb. 6 oz.

+  1,004 lb. 11 oz.

  1999 lb  17 oz  =  2000 lb 1 oz.

16 oz = 1 lb

Therefore,  

1999 lb  17 oz = 1999 lb + 16 oz + 1 oz = 1999 lb + 1 lb + 1 oz

b. 24 T 1,507 lb 12 oz.

   + 7 T 938  lb  6 oz.

      31 T  2445 lb  18 oz

2000 lb = 1 T.

16 oz = 1 lb

Therefore,

31 T  2445 lb  18 oz = 31 T + 2000 lb + 445 lb + 16 oz + 2 oz

                                 = 31 T + 1 T + 445 lb + 1 lb + 2 oz

c.     6 T.                 14 oz.  

   +  11 T. 1,949 lb.

   +                          8 oz.

   +   5 T. 49 lb.      15 oz.

     22T.  1998 lb.   37 oz.

     22T.  1998 lb.   37 oz. = 22 T + 1998 lb + 16oz + 16 oz + 5 oz.

                                          = 22 T + 1998 lb + 1 lb + 1 lb + 5 oz.

                                          = 22 T + 2000 lb + 5oz

                                           = 22 T + 1 T + 5 oz.

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

he will have 300 because he is really broke and 300 is in his imangine

step-by-step explanation: he ehe heh step by the thy