Prove that in any triangle the length of a side is less than the half of the perimeter. in statement reason .

In a triangle, the length of a side is less than the half of the perimeter.

Let's assume that the sides of a triangle are 8cm, 9cm and 10cm. The perimeter of a triangle is gotten by the addition of all its sides. Therefore, the perimeter will be:

= 8cm + 9cm + 13cm

= 30cm

Therefore, half of the perimeter is 30/2 = 15cm

Since the values of the sides are 8cm, 9cm and 10cm, then they're lesser than the half of the perimeter.

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Let be the sides of a triangle and its perimeter.

For any triangle, the below is true.

So

Now, let's write the inequalities for the thesis and prove they're true.

As a result, I got the exact same inequalities that are true for any triangle. Q.E.D.

there are no short passages to look at

x = -2

y = 848

step-by-step explanation:

plug in the numbers