Third-degree, with zeros of 1-i, 1+i, and 3, and and a leading coefficient of -7

zeros of 1-i, 1+i, and 3

We need to find a third degree polynomial  

if we are given with three zeros p, q and r then polynomial   can be written as

 a (x-p) (x-q) (x-r)

Leading coefficient is -7

So a= -7

Replace all the zeros

-7 ( x- 3) (x-(1-i)) (x-(1+i))

-7(x-3)(x-1+i) (x-1-i)

 ( the value of i^2 = -1)

Multiply (x-3) inside the second parenthesis

Now multiply -7 inside the parenthesis. the required polynomial is

b

step-by-step explanation:

a difference is the result of subtraction. while each of these expressions has subtraction in it, a difference will be the result when subtraction is the last operation applied in the order of operations for the expression. this means subtraction must be outside of the parenthesis. only b has this.