Using the polynomials q = 3 x2 + 5 x - 2, r = 2 - x2 , and s = 2 x + 5, perform the indicated operation. q - [ r + s ]

4x^2 + 3x - 9

Step-by-step explanation:

First, add together functions R(x) and S(x).  Stack them vertically and combine like terms:

R(x) = 2 - x^2

S(x) = 2x + 5

(R+S)(x) = -x^2 + 2x + 7

Now subtract the above result from Q(x):

Q(x) - (R(x) + S(x)) =  3x^2 + 5x - 2  + x^2 - 2x - 7, or 4x^2 + 3x - 9

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

according to egenuity the answer is

step-by-step explanation:

d. 344.22