The table of values represents a function f(x). how much greater is the average rate of change over the interval [9, 10] than the interval [5, 8] ? enter your answer in the box.

- The interval  [9, 10] is 1,375% greater than the interval [5, 8].

- The interval  [9, 10] is 14.75 times greater than the interval [5, 8].

Step-by-step explanation:

1. To solve this problem you must apply the following formula:

2. Let's calculate the average rate of change of each interval:

a) Interval [9,10]:

b) Interval [5,8]:

3. The difference is:

4. In percentage:

5. You have that the interval [9,10] is 14.75 times greater than the interval [5,8], as you can see below:

-4

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;