Is it possible to place 59 cans into three boxes so that the third box has 9 more cans than the first box and the second box has 4 less cans than the third box?

YES!

Step-by-step explanation:

First Box: x

Second Box: (x + 9) - 4  = x + 5

Third Box: x + 9

Total: 59

First Box + Second Box + Third Box = Total

     x        +       x + 5              x + 9      =   59

3x + 14 = 59

      -14  -14        

3x       =  45

÷3          ÷3        

        x = 15

Since 15 is a whole number (not a fraction), then it is possible.                            

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step-by-step explanation:

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