The equation of a hyperbola is x^2-4y^2-2x-15=0. what is the width of the asymptote rectangle?

 8

Step-by-step explanation:

x² - 2x  + ___ - 4y²  = 15 + ___

x² - 2x  + 1 - 4y²  = 15 + 1

(x - 1)² - 4(y)² = 16

width of rectangle is 2 = 2(4) = 8

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8