What are the two least likley sums to be rolled on two regular dice? why?

I think its 2 and 12

Step-by-step explanation:

Any double is not so likely as  say a 7 ( there are more ways to get a 7 than say  a double 1  because a 7 may be  a 6&1 , 2&5 or 3&4 but there's one 1 way to get  a double 1).

I think it must be 2 (double 1) and 12 ( double 6)  because there are no other ways to get these totals. Other doubles can give same value as other combinations For example  double 2  =  value  4 and 3 and 1 = 4.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

idk lol xd

step-by-step explanation:

ez do it yourself lazy