Need quick according to an x/y table, when x = –3, y = 21; when x = 4, y = –28; and when x = 5, y = –35. type the constant of variation, k. just type a number (possibly a fraction, with a slash). if this is not direct variation, type the word no.

According to an x/y table, when x = –3, y = 21; when x = 4, y = –28; and when x = 5, y = –35.

when x = –3, y = 21

If it is a direct variation then it satisfies y = kx

Lets plug in -3  for x  and 21  for y and find out k

y = kx

21= k (-3)

Divide by -3 on both sides

So k = -7

Lets check whether k = -7 for the other two set of values

when x = 4, y = –28,

-7 times 4 = -28

when x = 5, y = –35

-7 times 5 = -35

k =-7 satisfies all the set of values

So constant of variation k = -7

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !