Determine the solution x^2 - 3x -28 ≥ 0

The required solutions to the quadratic inequality are x ≥ 7 and x ≥ -4

Given the quadratic inequality;

x² - 3x -28 ≥ 0

Factorize the given inequality as shown:

x² +4x-7x -28 ≥ 0

(x²+4x)-(7x+28) ≥ 0

Factor out the common term

x(x+4)-7(x+4) ≥ 0

(x-7)(x+4) ≥ 0

x-7 ≥ 0 and x+4 ≥ 0

x ≥ 7 and x ≥ -4

Hence the required solutions to the quadratic inequality are x ≥ 7 and x ≥ -4

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x^2 - 3x -28 ≥ 0

factor

(x-7) (x+4) ≥ 0

x=7  x=-4

we have three regions where the answers can lie

x<-4  between -4 and 7  and x>7

pick a point and see if it works

x=-10

(-10-7) (-10+4) ≥ 0

negative * negative  is greater than 0 so this is a solution   x< -4

x=0

(0-7) (+4) ≥ 0

negative * positive  is less than 0 so this is  not a solution  

x=10

(10-7) (10+4) ≥ 0

positive * positive is greater than 0 so this is a solution   x>7

We have two regions that work

x<-4 and x>7

agree

step-by-step explanation:

ask i dont know either ; (

step-by-step explanation: