(1, 22) and is parallel to the line given by y = 14x - 3.do not use parenthesis on the y-side.

the equation of the line that is parallel to y=14x-3 and goes through (1, 22) is y=14x+8

Step-by-step explanation:

y=14x-3

y-y1=m(x-x1) where m is the slope and (x1, y1) is the given point (1, 22)

y-22=14(x-1)

plug in m=14, x1= 1 and y1= 22

y-22=14x-(14)*(1) distribute 14

y-22=14x-14 multiply

y=14x-14+22 add 22 to both sides to isolate (leave alone) y

y+14x+8

Hope this helped! Have a good day. :)

7

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length