Can i have some with these questions for my homework.

The answer is

1) 2

2) 5

Step-by-step explanation:

1) =\frac{\sqrt{2}\sqrt{2}\sqrt{5}}{\sqrt{5}}

= =\frac{\sqrt{2}\sqrt{2}\sqrt{5}}{\sqrt{5}}

= 2

2) \sqrt{99}+\sqrt{44}

\sqrt{99}=3\sqrt{11}

and

\sqrt{44}=2\sqrt{11}

So

3\sqrt{11}+2\sqrt{11}

= 5\sqrt{11}

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

=

x=0.8898305 is the answer to that equation