Will mark describe the graph of the function f(x) =  3-x2+3x-2. include the y-intercept, x-intercepts, and the shape of the graph.   show all of your work for finding x and y-intercepts.

The y-intercept is (0,1).  The x values at the horiz. intercepts are:

{ (-3+√5)/2, (-3-√5)/2 }.  Graph is that of a parabola that opens down.

Step-by-step explanation:

It'd be helpful to rewrite f(x) = 3-x2+3x-2 with the powers of x in descending order and using " ^ " to denote exponentiation:

f(x) = -x^2 + 3x -2 + 3, or

f(x) = -x^2 + 3x + 1

y-intercept:  let x = 0.  Then f(0) = 1.  The y-intercept is (0,1)

x-intercepts:  let y = f(x) = 0 = -x^2 + 3x + 1.  Let's use the quadratic formula with a = -1, b = 3 and c = 1 to determine the roots of this polynomial.  The discriminant, b^2-4ac, is 9-4(1)(1), or 5.

Thus, there are two real, unequal roots.  They are:

       -3 plus or minus √5

x =  

                     2

or { (-3+√5)/2, (-3-√5)/2 }

These are your two horizontal intercepts, where the function is zero.

Because the coefficient -1 of the x^2 term is negative, the parabola representing this function opens down.

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.

hint: which coefficient is a multiple of 360°?

step-by-step explanation: