In a triathlon, jenny swam for 1 hour, biked for 1.75 hours, and ran for 1 hour. her average biking speed was 2 times her average running speed, and her average running speed was 8 times her average swimming speed. the total distance of the triathlon was 55.5 kilometers. write and solve a linear equation to calculate jenny’s average swimming speed (x) in kilometers per hour. give your answer to the nearest tenth. asap 30 points

28r + 8r + r = 55

Step-by-step explanation:

Some values you know (given or calculated) and some things you do not know.

             RATE         TIME         DISTANCE

BIKE          2*8r         1.75

RUN           8r

SWIM           r            1

Total                                     55

Give a variable to unknown running speed and fill in everything.

             RATE         TIME         DISTANCE

BIKE          16r         1.75           28r        

RUN           8r            t            8rt

SWIM           r            1             r

Total                                     55

Notice some trouble? WHY? I missed seeing the "ran for one hour". the variable t is KNOWN! This will be corrected here:

             RATE         TIME         DISTANCE

BIKE          16r         1.75           28r        

RUN           8r            1            8r

SWIM           r            1             r

Total                                     55

Calculations used to fill out the graph:

Then her running speed was 8r,

and her biking speed was 2*(8r) = 16r.

Swimming for 1    hour, Jenny covered the distance of 1*r = r kilometers.

Biking   for 1.75 hour, Jenny covered the distance of 1.75*16r = 28r kilometers.

Running  for 1    hour, Jenny covered the distance of 1*2r = 8r kilometers.

Everything is filled and looks good. There is a sum of distances in just the one single variable, r.

Solve for r, and this is the swimming speed.

28r + 8r + r = 55

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answer: d.) the total number of protons and neutrons is 15

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80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh