Suppose a population of 50 crickets doubles in size every 3 months. how many crickets will there be after 2 years?

This is a Geometric Progression problem.

We can use the formula

= a1 +

= 50 x 2^(8-1)

50 is starting number

2 is doubled

8 is how many sets of 3 months in 2 years

= 50 x 2^(7)

= 50 x 128

= 6400

true

step-by-step explanation:

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²