Solve for x.-15x+60< 105 and 14x+11< -31a). x< -3b).x> -3c).x=-3d). there are no solutions e). all caluse of x are dolutions

-15x+60<105 and 14x+11<-31

-15x+60<105 subtract 60 from each side

-15x <45

divide by -15 (flips the inequality)

x>3

14x+11<-31

subtract 11 from each side

14x < -42

divide by 14

x<-3

Answer : there are no solutions since x>3 and x<-3 they are mutually exclusive (they both can't happen at the same time)

78.59 is the mean

step-by-step explanation:

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