[50 pts.] draw the image of rst under the dilation with scale factor 5/3 and center of dilation (2,-2) . label the image r's't'. show your work.

Given coordinates of the triangle RST are R(2,1), S(2,-2) and T(-1,-1).

Center of center of dilation is (2,-2).

Because center of dilation is (2,-2) so the coordinates of dilated image S(2,-2) would stay same.

Now, we need to apply rule for dilation with the scale factor 5/3.

Each of R(2,1), and T(-1,-1) would be and R' and T' would be in ratio 5/3.

We will extend RS to 5 units and TS also 5 units.

The new resulting image would be dilated triangle by a scale factor 5/3.

New coordinates would be

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

d is the answer

step-by-step explanation: