Assume that a particular professional baseball team has 10 pitchers, 6 infielders, and 9 other players. if 3 players names are selected at random from the team's roster, determine the probability that all 3 are infielders.

there are 25 players on the team (10+6+9)

there are 6 infielders

They are picking without replacement

6/25 * 5/24 * 4/23

rearranging

6*4/24 *5/25 *1/23

1 *1/5 *1/23

1/115

1/115

Step-by-step explanation:

Given

there is 10 pitchers,6 infielders and 9 other players

3 players are selected at random

no of ways in which 3 infielders can be selected is

no of ways in which 3 players out of 25 players can be selected is

Therefore required probability is

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

2

step-by-step explanation: