What is the completely factored form of f(x)=x3−7x2+2x+4? f(x)=(x−1)(x−(3+13−−√−(3−13−−√)) f(x)=(x+1)(x−(3+13−−√−(3−13−−√)) f(x)=(x+1)(x−(3+52−−√−(3−52−−√)) f(x)=(x−1)(x−(3+52−−√−(3−52−−√))

Factored form is

f(x)= (x-1)(x-3+√(-5))(x-3-√(-5))

Step-by-step explanation:

Given that  

f(x)=x3−7x2+2x+4

To solve for x  we factorise the right side

f(x)=x3−7x2+2x+4

Let us substitute x for various values to check whether remainder is zero.

i.e. f(1) = 1-7+2+4  =0

Hence x-1 is a factor

Do synthetic division to find the quotient

1       1    -7    2    4

              1     -6   -4

        1    -6    -4   0

i.e. we get remainder 0 and quotient as

x^2-6x-4

Use completion of squares method to solve this

x^2-6x-4

= (x-3)^2+5=0

x-3= ±√(-5)

Or x=1,3+√(-5,)  3-√(-5,)

Are the roots

Factored form is

f(x)= (x-1)(x-3+√(-5))(x-3-√(-5))

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

step-by-step explanation: