If 5 boys and 2 girls are seated at random in a toboggan, what is the probability that 4 or more boys are seated in consecutive places? show your work.

 3/7  

So the total number of children in a toboggan = 7 (5 boys + 2 girls)

The possible arrangement could be (7, 2) = 21 ways

Boys can be seated in between the girls in (3, 1) = 3 ways

And 4 boys can be seated in between the girls in 3 ways which would leave 2 places for the left behind boy

Probability = (6+3)

= 9 / 21

= 3/7  

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23