Tell whether y=-3(x+1)^2+4 has a minimum or a maximum value. then find that value.

maximum value at y = 4

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = - 3(x + 1)² + 4 is in this form

with vertex = (- 1, 4) and a = - 3

• If a > 0 then vertex is a minimum

• If a < 0 then vertex is a maximum

here a < 0

(- 1, 4 ) is a maximum and maximum value = 4