Calculate the distance between (2 + 2i) and (6 + 5i).

u − v = 〈s − a, t − b〉

u − v = √(s − a)2 + (t − b)2

EXAMPLE 1 Finding the Distance Between Points

in the Complex Plane

Find the distance between the points 2 + 3i and 5 − 2i in the complex plane.

Solution

Let a + bi = 2 + 3i and s + ti = 5 − 2i. The difference between the complex

numbers is

(5 − 2i) − (2 + 3i) = (5 − 2) + (−2 − 3)i = 3 − 5i.

The distance is

d = √32 + (−5)2 = √34 ≈ 5.83 units

Step-by-step explanation:

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!