Determine the possible number of negative zeros when f(x)=x^5 - 3x^3 + 2x^2 + 5x - 4

using Descartes' rule of signs

Count the number of sign changes in f(x)

+ \ - / + / + / -

There are 3 sign changes, hence a maximum of 3 possible positive roots

f( - x) = - + 3x³ + 2x² - 5x - 4

count the number of sign changes in f( - x)

- / + / + / - / -

There are 2 sign changes, hence a maximum of 2 possible negative roots

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )

i think the correct option is the second option.