In a parallel circuit, et = 208 v, r = 33 kω, and xl = 82 kω. what is the apparent power?

Apparent power is 1.413Volt-Amps.

Step-by-step explanation:

We are given that in a parallel circuit,,R=33kΩ and =82kΩ.

And we are asked to find apparent power.

Apparent power is the combination of true power and reactive power.

In other words, we can say that in a power triangle apparent power is the hypotenuse where as true power and reactive powers are sides.

Let us find true power , reactive power first and the using Pythagorean theorem we can find apparent power.

True power=

Reactive power=

Hence apparent power=

answer: b.48 for

step-by-step explanation: