What is the perimeter of a triangle abc with vertices a(-1,3) b(2,3) c (-1,-3) a) 15.71 b)16.55 c) 14.20 d) 18.41

15.71

Step-by-step explanation:

Length AB =  sqrt ( (3-3)^2 + (2- - 1)^2) =  sqrt9 = 3

Length BC =  sqrt ( (-3-3)^2 + ( -1-2)^2) =  sqrt  45

Lemgth CA =  sqrt( 6^2) + (-1 - -1)^2 = sqrt 36 = 6

Perimeter = 3 + 6 + sqrt45

= 15.71

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

the answer is

d.

5.3066 m2

step-by-step explanation: