For every gallon of water in a swimming pool, you’ instructed to add four grams of chlorine. how many grams of chlorine would you add to a pool containing 13 gallons of water?

52

Step-by-step explanation:

Multiply grams per gallon times gallons to get grams.

52 grams

Step-by-step explanation:

This problem can be solved simply by applying the ratio method.

We know that 1 gallon of waters requires 4 grams of Chlorine in the swimming pool, so we can assume the number of grams of Chlorine required for 13 gallons of water to be x.

So we can write it as:

So x will be equal to

Therefore, 52 grams of Chlorine is required for 13 gallons of water in the swimming pool.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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