What is the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5? y = x – 8 y = x + 1 y = x + 1 y = x + 10

The equation of the parallel line would be y = 3/2x + 10

Step-by-step explanation:

In order to find this, we first need to find the slope of the first line. We can do this by solving for y.

2x + 3y = -5

3y = -2x - 5

y = -2/3x - 5/3

Now we know the slope to be 3/2 since perpendicular lines have the opposite and reciprocal. So we can use point-slope form to find the equation of the line.

y - y1 = m(x - x1)

y - 1 = 3/2(x - -6)

y - 1 = 3/2x + 9

y = 3/2x + 10

While this doesn't match any of your options, it is correct for the given parameters.

The correct answewr choice is y = 3/2x + 10 (D)

Step-by-step explanation:

I just took the Algebra quiz.