Determine the x- and y-intercepts of the graph of y=1/4 x−2 and make a table of ordered pairs for the equation. y=−1/3x+1 graph is for both questions

Step-by-step explanation:

Problem A

Basically all you have to do is put in 0 for x to give the y intercept and

0 in for y to give the x intercept. Here we go

x intercept

y =0

0 = (1/4)x -2     Add 2

2 = (1/4)x          Multiply both sides by 4

2*4 = x              Combine and switch

x = 8

x = 0

y = (1/4)*0  - 2

y = -2

Intercept points

x_intercept: (8,0)

y_intercept: (0, - 2)

Problem 2

Essentially you make up the table by using random numbers meaning any number for x and solve for y.

x = -3

y = (-1/-3)(-3) + 1

y = -3/-3 + 1

y = 1 + 1

y = 2

y = 6

y = (-1/3)*6 + 1

y = -6/3 + 1

y = - 2 + 1

y = - 1

two other points are

(0,1) and

(-6,3)

To create the graph go to Desmos.

The red graph is y = (1/4)x - 2 The two intercepts are marked.

The blue graph is y = (-1/3)x + 1

The 4 points from the table  are on the blue line. The table is on your left.

If you see a mistake let me know. This is the noisiest place I've ever been in.

its not b

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.