The product of two numbers is 88. the sum of the two numbers is 26. what are the numbers

let's take the numbers a and b

setup a system of equations:

a+b=26

a*b=88

now solve it using substitution:

1) b=88/a

2)(substitute) a+ 88/a = 26  

3)(add fractions) (a^2+88)/a=26

4)(get polynominal) a^2-26a+88=0

5)(factor) (a-22)(a-4)=0

6) (solve) a=22 OR a = 4

7) (after checking) a= 22 or a=4

and b=22 or b=4

idk

step-by-step explanation:

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: