Find the point on the circle x^2+y^2 = 16900 which is closest to the interior point (30,40)

Answer-

(78,104) is the closest to the interior point.

Solution-

The equation of the circle,

As the point will be on the circle, so the coordinate of the point will be,

The distance "d' between the point and (30,40) is,

Now, we have to calculate x for which d is minimum. d will be minimum when    will be minimum.

Let,

Finding the critical values,

Then,

f''(x) is positive, so f(x) will be minimum at x=78

For x = 78, y will be

Therefore, the point is (78,104)

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

answer: ur v dumb

step-by-step explanation: