The equation of line j is y + 5 = 2(x − 8. line k includes the point (-4, -3) and is perpendicular to line j. what is the equation of line k?

y = - x - 5

y + 5 = 2(x - 8) is in point-slope form

y - b = m(x - a) ( m is the slope and (a, b) a point on the line )

here the slope m = 2

the slope of a line perpendicular to this is equal to - = -

line k goes through (- 4, - 3), hence equation is

y + 3 = - (x + 4) ← in point-slope form

y + 3 = - x - 2 ( distributing )

y = - x - 5 ← in slope-intercept form

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step-by-step explanation:

boxplot e is the answer