Acertain disease has an incidence rate of 0.2%. if the false negative rate is 5% and the false positive rate is 2%, compute the probability that a person who tests positive actually has the disease.

P(I)=Incidence rate of a disease= 0.2 %

P(F .N) =False negative rate = 5%

P (F.P)=False positive rate= 2%

Probability that a person who tests positive actually has the disease

                         =  

                 =  

                 =  

                 =

50 min

step-by-step explanation:

they will be decreasing both their times in half

60 / 2 = 30

40/2 = 20

30 + 20 = 50

-232

step-by-step explanation: