An island has some portion submerged in water. point a on the island is at negative 5 over 4 feet from the surface of the sea. point b on the island is at negative 2 over 3 feet from the surface of the sea. because negative 2 over 3 feet > negative 5 over 4 feet, what is true about the distance of the two points from the surface of the sea? a. point a is closer to the surface of the sea than point b. b. point b is closer to the surface of the sea than point a. c. both points are 1 and 11 over 12 feet from the surface of the sea. d. both points are 7 over 12 feet from the surface of the sea.

The answer would be a. Point A is closer to the surface of the sea than point B.

-2/3 has a smaller absolute value than -5/4, meaning that -2/3 is close to 0

A. Point A is closer to the surface of the sea than point B.

Step-by-step explanation:

Point A on the island is at -5/4 feet from the surface of the sea.

Point B on the island is at -2/3 feet from the surface of the sea.

-2/3 feet > -5/4 feet

=> -0.666 feet > -1.25 feet

-0.666 is close to zero.

So, answer will be A. Point A is closer to the surface of the sea than point B.

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

fdvs

step-by-step explanation: vsfdvsfvd