Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. a(n) = 1 + (n – 1)(–5.7) 1, –21.8, –56 –5.7, –21.8, –51.3 1, –16.1, –50.3 0, –17.1, –51.3 if someone answers this, i'd like if someone could me to know how to solve it too, and you!

1, - 16.1, - 50.3 ← third on list

To find the required terms, substitute n = 1, 4, 10 into the rule and evaluate

A(1) = 1 + (1 - 1)(- 5.7) = 1 + 0 = 1

A(4) = 1 + (4 - 1)(- 5.7 ) = 1 + (3 × - 5.7 ) = 1 - 17.1 = - 16.1

A(10) = 1 + (10 - 1 )(- 5.7) = 1 + (9 × - 5.7) = 1 - 51.3 = - 50.3

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.