Shenelle has 100 meters of fencing to build a rectangular garden. the garden's area (in square meters) as a function of the garden's width www (in meters) is modeled by: a(w)=-(w-25)^2+625. what is the maximum area possible?

Alright, lets get started.

The graden's area is given as :

For maximization of area, a'(w) should be equal to zero.

Simplifying :

w = 25 meters

Fencing is given 100 meters that means that will equal to its perimeter,so

Plugging w as 25

Dividing 2 in both sides

Means for maximum area of rectange, l should be 25 and w should be 25 too.

So, area (maximum) =

Area(maximum) = 625 square meters    :    Answer

Hope it will help :)

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

the answer will be b x² +x-1

step-by-step explanation: