If the equation below is solved by graphing, which statement is true? log(6x+10)=log1/2x the curves intersect at approximately x = 0.46. the curves intersect at approximately x = 0.75. the curves intersect at approximately x = 1.11. the curves intersect at approximately x = 3.07.

.46

Step-by-step explanation:

If you graph the function, you can see where the two logs intersects. View the image I have attached.

If the equation log(6x+10)=log(1/2) x is solved by graphing, the curves intersect at approximately x=0.46

Step-by-step explanation:

Equation

log(6x+10)=log(1/2) x

We must graph two functions:

f(x)=log(6x+10) and

g(x)=log(1/2) x→g(x)=log0.5 x

If we graph these two equation the point of intersection is approximately (0.464, 1.107)=(x,y)

x=0.464→x=0.46

y=1.107→y=1.11

2,600 divided by 80 = 32.5

step-by-step explanation:

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol